Passenger cars and trucks depart from Party A and Party B respectively and meet at a distance of 5 kilometers. After the encounter, the car continued to drive at the original speed, heading for Party A and Party B respectively. When the speed ratio of passenger cars and trucks is 7/8: 1 = 7: 8, the distance each car travels at the same time is also 7: 8.

(It should be 5 kilometers from the midpoint. )

When they met, there were more buses than trucks: 5× 2 = 10 (km).

The ratio of this 10km to the whole journey is 8/(7+8)-7/(7+8) =115.

From the local to the whole, we can know that the distance of the whole is10 ÷115 =150 (km).

When the total freight car distance is 150km, the passenger car distance is150× 7 ÷ 8 =131.25 (km).

Therefore, the distance to the terminal station B is150-131.25 =18.75 (km).