Ann? =a(n- 1)a(n+ 1)
(pn? +xq? )? =[p(n- 1)? +xq? ][p(n+ 1)? +xq? ]
Pack up, take it
-p(2an+p)=0
P=0 or an=-p/2
When p=0, an=xq?
That is, only when the series {an} is a constant series, all terms are equal to -p/2 (p≠0) or xq? (x, q≠0), there are three consecutive terms to form a geometric series. In other cases, they all constitute geometric series.