According to the known c12 = C2 2 = C2C2, that is, a12-b12 = a22+b22 = C2,
So B 1 2 = A 1 2-C 2, B2 2 = C2-A2 2,
Their focal triangle areas are equal, that is, b12 * tan (π/6) = B2 2 * cot (π/6).
So (a12-C2) *1/3 = C2-a22,
So a12-c 2 = 3 (c 2-a22c2-a22),
The two sides divided by c 2 are (a1/c) 2-1= 3 (1-(a2/c) 2).
So (A 1/c) 2+3 (A2/c) 2 = 4,
That is 1/E 1 2+3/E2 2 = 4.