What is the expression of the exponential function f(x)= 1/3 of the straight line y= 1?
F(x) = (1/3) XG (x) and f (x) are symmetrical about the straight line y= 1; To find g(x), let P(x, y) be any point on the g(x) image, and the symmetrical point P'(x', y') {x = x' {y+y' = 2 = = > {x'=x{y'=2-yP'(x, 2-y)P' is on the f(x) image, so 2-y = (1/3) xy = 2-(1/3) XG (x). ...