When a person gets a pair of A's, it is almost 3*4/5 1/52=.

0.45%, the probability of another person getting two aces is 2/50/49=0.08%.

So:

0.45%*0.08%*(6*5

/2) (possibility of randomly selecting two people from six people) = 1

About one in ten thousand.

Between 0.54 and 0.57.