2.75%
Mass fraction of iron oxide = mass fraction of iron element/mass fraction of iron oxide
52.5%/( 1 12/ 160)=75%
Let the theoretical calculation require that the quality of this ore is X. ..
Fe2O3+3CO=2Fe+3CO2
160 1 12
75%x 42t
160/75% x = 1 12/42
X = 80t.
Answer: If you want to get 42t pure iron, you need 80t of this ore in theory.