Fdt futures time
Of course not. First of all, according to the law of conservation of mechanical energy, the ball will be released at rest from the same height and reach the ground at the same speed. This is easy to understand. There is a theorem called momentum theorem, mdv=Fdt, where m is mass, f is resultant force, dv is velocity change, and dt is time change. Because the speed of the final object changes the same, the mass remains the same, and the greater the resultant force, the shorter the time.