Current location - Trademark Inquiry Complete Network - Trademark inquiry - The trademark pattern of a certain product is as shown in the figure (the shaded part in the figure). It is known that the diameter of ⊙O is AB⊥CD, and AB=8cm. The arc AB has D as the center and DA as
The trademark pattern of a certain product is as shown in the figure (the shaded part in the figure). It is known that the diameter of ⊙O is AB⊥CD, and AB=8cm. The arc AB has D as the center and DA as
The trademark pattern of a certain product is as shown in the figure (the shaded part in the figure). It is known that the diameter of ⊙O is AB⊥CD, and AB=8cm. The arc AB has D as the center and DA as the radius.
∵AB is the diameter
∴∠ADB=90°
∵AB=8, diameter AB⊥CD
∴AD= BD
According to the Pythagorean theorem: 2AD 2 =64
The solution is: AD=4 2 cm
According to the sector area formula:
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The area of ??the trademark pattern = 90π×32 360 =8πcm 2.