2.8/9 × 15/36 + 1/27

3. 12× 5/6 – 2/9 ×3

4.8× 5/4 + 1/4

5.6÷ 3/8 – 3/8 ÷6

6.4/7 × 5/9 + 3/7 × 5/9

7.5/2 -( 3/2 + 4/5 )

8.7/8 + ( 1/8 + 1/9 )

9.9 × 5/6 + 5/6

10.3/4 × 8/9 - 1/3

1 1.7 × 5/49 + 3/ 14

12.6 ×( 1/2 + 2/3 )

13.8 × 4/5 + 8 × 1 1/5

14.3 1 × 5/6 – 5/6

15.9/7 - ( 2/7 – 10/2 1 )

16.5/9 × 18 – 14 × 2/7

17.4/5 × 25/ 16 + 2/3 × 3/4

18. 14 × 8/7 – 5/6 × 12/ 15

19. 17/32 – 3/4 × 9/24

20.3 × 2/9 + 1/3

2 1.5/7 × 3/25 + 3/7

22.3/ 14 ×× 2/3 + 1/6

23. 1/5 × 2/3 + 5/6

24.9/22 + 1/ 1 1 ÷ 1/2

25.5/3 × 1 1/5 + 4/3

26.45 × 2/3 + 1/3 × 15

27.7/ 19 + 12/ 19 × 5/6

28. 1/4 + 3/4 ÷ 2/3

29.8/7 × 2 1/ 16 + 1/2

30. 10 1 × 1/5 – 1/5 × 2 1

3 1.50+ 160÷40 (58+370)÷(64-45)

32. 120- 144÷ 18+35

33.347+45×2-4 160÷52

34(58+37)÷(64-9×5)

35.95÷(64-45)

36. 178- 145÷5×6+42 420+580-64×2 1÷28

37.8 12-700÷(9+3 1× 1 1) ( 136+64)×(65-345÷23)

38.85+ 14×( 14+208÷26)

39.(284+ 16)×(5 12-8208÷ 18)

40. 120-36×4÷ 18+35

4 1.(58+37)÷(64-9×5)

42.(6.8-6.8×0.55)÷8.5

43.0. 12× 4.8÷0. 12×4.8

44.(3.2× 1.5+2.5)÷ 1.6 (2)3.2×( 1.5+2.5)÷ 1.6

45.6- 1.6÷4= 5.38+7.85-5.37=

46.7.2÷0.8- 1.2×5= 6- 1. 19×3-0.43=

47.6.5×(4.8- 1.2×4)= 0.68× 1.9+0.32× 1.9

48. 10. 15- 10.75×0.4-5.7

49.5.8×(3.87-0. 13)+4.2×3.74

50.32.52-(6+9.728÷3.2)×2.5

Example: Xiaoming reads a book. On the first day he read 35 pages, on the second day he read 56 pages, and on the third day he read 13/20 of the book. How many pages are there in this book?

Think: the number of units 1 is (the number of pages in this book is * * *), and it is unknown (division);

The calculation relationship is: (known quantity) ÷ (corresponding fraction of known quantity) = (quantity in 1)

Because the known quantity is * * * the number of pages of books read the next day, that is, (35)+(56),

The score corresponding to the known quantity is the score of the book read the next day, that is, (13/20);

So the formula is: ((35+56) ÷13/20 =140 (page)).

1, Xiaoming reads a book. On the first day, he read 1/4 of the book, the next day, he read 2/5 of the book, and the next day, he read 9 1 page. How many pages are there in this book?

Think: the quantity of unit 1 is (), and the unknown is ();

The calculation relationship is: () ⊙ () = ()

Because the known quantity is the number of pages of books read the next day, that is, (),

The score corresponding to the known quantity is the score of the whole book read the next day, that is, ()+();

So the formula calculation is: ()

Xiaoming has read a book. On the first day he read 1/4, and on the second day he read two-fifths of the books. The next day, he read 2 1 more pages than the first day. How many pages are there in this book?

Think: the quantity of unit 1 is (), and the unknown is ();

The calculation relationship is: () ⊙ () = ()

Because the known amount is the number of pages read the next day more than the first day, that is, (),

The score corresponding to the known quantity is the score of reading more books on the second day than on the first day.

Namely ()-();

So the formula calculation is: ()

There is a batch of goods. First day delivery14, second day delivery 3/5, leaving 18 tons. How many tons is this shipment?

Think: the quantity of unit 1 is (), and the unknown is ();

The calculation relationship is: () ⊙ () = ()

Because the known quantity is surplus goods, that is, (),

The score corresponding to the known quantity is the score of the remaining goods, that is,1-()-();

So the formula calculation is: ()

There is a batch of goods. First day delivery 1/4, second day delivery 3/5. The first day was 42 tons less than the second day. How many tons is this shipment?

Think: the quantity of unit 1 is (), and the unknown is ();

The calculation relationship is: () ⊙ () = ()

Because the known quantity is the weight shipped less on the first day than on the second day, that is, (),

The corresponding fraction of the known quantity is the fraction of the goods shipped less on the first day than on the second day.

Namely ()-();

So the formula calculation is: ()

What have you gained through practice? Specifically:

Thinking Training for Solving Fractional Multiplication Application Problems

For example, a wire is12m long, and 2/3 of it is cut. How many meters was cut off?

Think about it: whose 2/3 is cut off, the unit 1 is (the total length of iron wire), which is called (multiplication);

The calculation relationship is: (quantity in unit 1) × (score corresponding to the sought quantity) = (sought quantity).

Because the unit 1 is the total length of the iron wire, that is, (12m) is known,

How many meters are cut according to the required quantity? Its corresponding score is (2/3) of the total length of iron wire;

So the formula is: (12× 2/3 = 8 (m))

1, a wire length of12m, 2/3 was cut. How many meters are left?

Think about it: whose 2/3 is cut off, the unit 1 is (), which is called ();

The calculation relationship is: () × () = ()

Because the unit 1 is the total length of the iron wire, that is, () meters is known,

The required quantity is how many meters are left, and its corresponding fraction is the fraction of the total length of the remaining conductor.

Namely ()-();

So the formula calculation is: ()

A bag of rice weighs 50 kilograms. After eating 3/5, how many Jin is left?

Think about it: Who ate 3/5 of it, and the amount of 1 is (), which is called ();

The calculation relationship is: () × () = ()

Because the unit 1 is the weight of a bag of rice, that is, () kg is known,

The required amount is how many kilograms are left, and the corresponding score is a fraction of the total weight of the remaining rice.

Namely ()-();

So the formula calculation is: ()

There are 240 apple trees in the orchard, the number of pear trees is 5/8 of that of apple trees and the number of peach trees is 4/5 of that of pear trees. How many peach trees are there?

Think: whose pear tree is 5/8, and the first unit of 1 is (), which is called ();

The calculation relationship is: () × () = ()

In this way, the number of pear trees can be calculated first, and the formula is: ()

Think again: whose peach tree is 4/5, and the second unit of 1 is (), which is called ();

Because the quantity of the second unit 1 is the number of pear trees, that is, known () trees,

The demand is how many peach trees there are, and its corresponding score is 4/5 of the number of pear trees;

Column calculation is: ()

In this way, the comprehensive formula calculation is: ()

4. The construction team built a road with a length of1200m. 0/8 of the total length of 65438 was built on the first day, and 2/7 of the total length was built on the second day. How many meters are left?

Think: the quantity of unit 1 is (), which is called ();

The calculation relationship is: () × () = ()

Because the unit 1 is the total length of the highway, that is, () meters is known,

The demand is how many meters remain to be repaired, and its corresponding score is a fraction of the total length of the remaining road.

Namely1-()-();

So the formula calculation is: ()