Solution: According to the meaning of the problem,

∠∠KLM =∠TSM = 90°, ∠KML=∠TMS (reflection angle equals incident angle),

∴△KLM∽△TSM，

∴KLLM=

TSSM, i.e. 1.50.3=

TS25(4 points)

∴TS= 125(m)(3 integral)

So the height of this building is125m. (1 min