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For example, the diameter and height of the bottom surface of a cylindrical oil drum are all 4 decimeters. (1) How flat is the area around the oil drum where the trademark paper is to be affixed?
(1)3. 14×4×4=50.24 (square decimeter)

A: The area of trademark paper is 50.24 square decimeters.

(2) Transverse area of oil drum: 3. 14×4×4=50.24 (square decimeter).

Oil drum bottom area: 3.14× (4÷ 2) 2× 2 = 3.14× 22× 2 = 25.12 (square decimeter).

Surface area of oil drum: 50.24+25. 12=75.36 (square decimeter)

A: The surface area of the oil drum is 75.36 square decimeters.

(3)3. 14×(4÷2)2×4×0.8

=50.24×0.8

=40. 192 (kg)

A: This oil drum can hold 40.192kg of oil.