∴ab=bc∠BAC =∠BCA = 60。 ( 1)

∫ Quadrilateral ACDE is isosceles trapezoid ∠ EAC = 60, ∴ae=cd∠ACD =∠CAE = 60,

∴∠BAC+∠CAE= 120 =∠BCA+∠ACD，

That is ∠ BAE = ∠ BCD. (2 points)

In △ABE and △BCD, AB=BC, ∠BAE=∠BCD, AE=CD,

∴△ Abe△ ?△CBD. (3 points)

(2) solution: existence. The answer is not unique, such as △ ABN ∽△ CDN.

Proof: ∫△ABE?△CBD,

∴∠ABE=∠CBD，

∴∠BAC+∠ABE=∠BCA+∠CBD，

∴∠ANB=∠DNC，

∠∠Ban = 60 =∠DCN，

∴△ ANB ∽△ CND。 (5 points)

The similarity ratio is abdc = 21= 2; (6 points)

(3) Solution: ANCN=ABCD=2 is given by (2),

∴cn= 12an= 13ac(8 points)

Similarly, AM= 13AC,

∴ am = Mn = NC。 (9 points)

(4) Solution: Make the extension line from DF⊥BC to BC in F,

∫∠BCD = 120，

∴∠ DCF = 60。 ( 1o)

In Rt△CDF, ∴∠ CDF = 30,

∴CF= 12CD= 12，

∴DF=CD2？ CF2= 12？ ( 12)2=32; ( 1 1)

In Rt△BDF, ∫BF = BC+CF = 2+ 12 = 52, DF= praised and trampled. What's your comment on this answer? Put away comments//high quality or satisfaction or special types or recommended answers dottimewindow.iperformance & window.iperformance.mark ('c _ best',+newdate); Recommend lawyer service: If your problem has not been solved, please describe your problem in detail. Free professional consultation through Baidu Legal Pro | Serve the official certified lawyer consultation of Baidu Legal Pro that you may need | The average response time is 3 minutes | The problem solving rate is 99%| 24-hour online free consultation lawyer 19794 people are getting one-on-one answers. Jinan handed in the question four minutes ago in the hot summer, Wuhan Grassland Wind 1 minute ago and Qingdao Neverland two minutes ago. Other similar problems 20 12- 10-27= As shown in the figure, it is a diamond trademark of Xiaohong's design, and △ABC is an isosceles with a side length of 2. Quadrilateral ACDE is an isosceles trapezoid, AC∠ED, ∠ EAC = 60,102012-05-21is a diamond-shaped trademark as shown in the figure, △ABC is an equilateral triangle with a side length of 2, and quadrilateral ACDE is an isosceles trapezoid, AC ∠. It is the diamond trademark of Xiaohong's design, triangle ABC is an equilateral triangle with a side length of 2, quadrilateral ABDE is an isosceles trapezoid, AC is parallel to ED, and angle EAC52013-014 (201kloc-0/Yiyang) is the diamond trademark of Xiaohong's design. △ABC is an equilateral triangle with a side length of 2132013-01-27. As shown in the figure, it is a diamond trademark triangle designed by Xiao Cong. ABC is an equilateral triangle with a side length of 6, and the quadrilateral ABDE is equal to 22013-31(2018). 6? 1 Yiyang) is a diamond trademark designed by Xiaohong, △ABC is an equilateral triangle with a side length of 2.202016-0/-04, △ABC is an equilateral triangle with a side length of 2, the quadrilateral ACDE is an isosceles trapezoid, and AC∨ED, ∠ EAC. Ae12016-10-26 shows a diamond-shaped trademark designed by Xiaohong, where △ABC is an equilateral triangle with a side length of 2, the quadrilateral ACDE is an isosceles trapezoid, AC∠ED, ∠ EAC = 60. AE hasn't solved the lawyer's problem yet? The problem-solving rate of 39,874 online lawyers who immediately asked lawyers for a three-minute response time was 99%. Submit the question and the lawyer will call back for an answer. Consult a lawyer for free immediately. I handed in a question four minutes ago on a hot summer day in Jinan, waiting for you to answer it? Change and help more people? Download Baidu Know APP and grab a fresh experience. Know the APP with Baidu and grab a fresh experience immediately. There may be answers that others want to know in the camera of your mobile phone. Scan QR code to download illegal and harmful information about personal and corporate infringement complaints. Please select and submit a category below.

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