A teapot, with a height of 10CM and a diameter of 8cm, needs to be stamped with a trademark on its side, and the trademark joint is 1cm. What is the area of this trademark?
First of all, the length of the circle is necessary. The formula is C=πd, and the value of π is generally 3. 14. Then substitute the known conditions, and the circumference of the circle is C=3. 14×8=25. 12cm. Note: This is not the length of the trademark, but also 1cm at the joint, so the length of the trademark is 25.12+1= 26.12cm, and the height of the tea can is 10cm, so the height of the tea can is the width of the trademark. Tell me if you are weak, and pay attention to writing and answering ~