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The final math test paper in the second volume of the eighth grade
2009-20 10 school year second semester Nanchang final examination paper.

Mathematics Reference Answers and Grading Opinions of Grade 8 (Grade 2)

First, multiple-choice questions (this topic is entitled ***8 small questions, with 3 points for each small question and 24 points for * * *).

1.B 2。 B 3。 D 4。 C 5。 A six. A seven. B 8。 D

Fill in the blanks (this topic is entitled ***8 small questions, with 3 points for each small question and 24 points for * * *).

9.x≠ 1 10.7℃ 1 1。 If ab=0, then A = 0 12 500m 13.55.

14. 15.30 or 150 16. ① ③ ④

Third, solve the problem (this big question is ***3 small questions, 6 points for each small question, *** 18 points)

17. Solution: Original formula = …………………………………………………………………………………………….

=........................4 points.

=...................6 points.

18. solution: multiply both sides of the equation by X-2, .................. 1 min.

Get 3 = 2 (x-2)-x .................... 3 points.

The solution is x = 7, .................... 5 points.

Test: when x=7, x-2 = 5 ≠ 0. ∴ x = 7 is the solution of the original equation ............................................................................................................................

19. Solution: (1)∵, ................ 1 fraction.

Any score divided by the previous one is equal to 2 points.

(2) The seventh score is ... the seventh score.

The nth score is 6.

4. Inquiry questions (this big question is ***2 small questions, with 8 points for each small question, *** 16 points)

20. certificate: (1) in rectangular ABCD, OB=OD, AB‖CD, .................. 1.

∴∠OBE=∠ODF,∠e =∠f .∴△BOE?△DOF ...........................................................................................................

(2) When EF⊥AC, the quadrilateral AECF is a diamond, because

According to (1), △ BOE △ DOF, ∴ OE = of .........................., 5 points.

Oa = oc, ∴ quadrilateral AECF is a parallelogram, and ........................ scored 6 points.

∵EF⊥AC, ∴ quadrilateral AECF is a diamond ........................................................... 8 points.

2 1. Solution: (1) A democratic appraisal score is 25%× 100× 1=25, ...

The democratic appraisal score of B is 40%× 100× 1=40, and ………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………….

The evaluation score of Party C's democracy is 35%× 100× 1=35, and …………………………………………………………………………………………………………………………………………………………………………………………………………….

(2) The comprehensive score of A is MA = 25a+165 (1-a) =165-140a. ....................................................................................................

The comprehensive score of B is MB = 40a+160 (1-a) =160-120a. ......................................... has 5 points.

The comprehensive score of C is MC = 35a+170 (1-a) =170-135a. ..........................................................................................................

∵ B was finally hired, and ∴ B should have the highest comprehensive score.

From M B to MA = (160-120a)-(165-140a) = 20a-5 > 0. Get a >.

From M B to MC = (160-120a)-(170-135a) =15a-10 > 0. Get a >.

∴ If Party B is finally hired, the value range of A is < A < 1 ...........................................................................................................................................

V. Comprehensive questions (this big question * * 1 small question, ***8 points)

22. Solution: (1) From the inverse proportional function image, we get 2 =-k and ....................... 1 min.

∴ The analytical formula of inverse proportional function is .................................................................................................................................................................

From the image of linear function y = ax+b, the solution is ….

The analytical formula of ∴ linear function is y =-x+ 1 ...............................................................................................................................................

(2) The images of two functions are as shown in the figure, while B(2,-1) ......................................................................................................................................

(3) s △ AOB = s △ AOC+s △ BOC = ........................... 8 points.

Six, the topic of learning (the big topic * * 1 small topic, *** 10 points)

23.( 1) A: when point p is on the DC extension line, DF-BE = ef. ....................................................................................................................................

Certificate: In the square ABCD, there are AB=AD and ∠ Bad = 90.

That is, ∠ BAE+∠ DAF = 90 ......................, 3 points.

∵BE⊥AP,DF⊥AP,∴∠BEA=∠DFA=90。

∴∠Abe+∞∠BAE = 90。 ∴∠ Abbe = ∠ DAF .................................................................... 4 points.

∴△ Abe△ DAF .......................... 5 points.

∴BE=AF,AE = DF。 ∴ DF-BE = AE-AF = EF ..................................................................................................................................

(2) Answer: When point P is on the extension line of CD, line segments BE, DF and EF do not exist in the relationship in (1), but satisfy the relationship BE+DF = EF. ............................................................................................................